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A formula for calculating the unbiased estimation of the population variance from n finite samples is:
The method of calculation may be more easily understood from the table below where the mean is 8.
| i | xi | xi − mean | (xi − mean)2 |
| (index) | (datum) | (deviation) | (squared deviation) |
| 1 | 5 | −3 | 9 |
| 2 | 7 | −1 | 1 |
| 3 | 8 | 0 | 0 |
| 4 | 10 | 2 | 4 |
| 5 | 10 | 2 | 4 |
| n = 5 | sum = 40 | 0 | 18 |
Note: Details of the variance calculation:
338 = [52 + 72 + 82 + 102 + 102]
40 = [5 + 7 + 8 + 10 + 10]
Therefore a simple algorithm to calculate variance can be described by the following pseudocode:
double sum; double sum_sqr; double variance; long n = data.length; // the number of elements in the data array (the actual syntax is language-specific) for i = 1 to n sum += data[i]; sum_sqr += ( data[i] * data[i] ); end for variance = ((n * sum_sqr) - (sum * sum))/(n*(n-1));Another algorithm which avoids large numbers in sum_sqr while summing up
double avg = 0; double var = 0; long n = data.length; // number of elements for i = 1 to n avg = (avg*i + data[i]) / (i + 1); var = (var * (i - 1) + (data[i] - avg)*(data[i] - avg)) / i; end for return var; // resulting variance Statistics